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 Problems with Boolean Algebra~~!
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Posted on 09-13-07 11:54 PM     Reply [Subscribe]
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HI Yekloyatri

here is your solution for

1 A'B +AB' + AB + A'B' = 1

rearrange them first

A'B +A'B'+ AB +AB' = 1
A'(B + B') + A(B +B') = 1 (since B +B' = 1)
A + A' =1
1=1
proved
hope it will help
do same thing with second problem
 
Posted on 09-14-07 12:07 AM     Reply [Subscribe]
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basic boolean rules can be referred to @
http://www.ee.surrey.ac.uk/Projects/Labview/boolalgebra/index.html#commutativelaw

A'B + AB' + AB + A'B'
= (A'B +A'B')+(AB'+AB)
=A'(B+B')+A(B'+B)
=A' (1) + A (1)
= A' + A
= 1

X' + XY + XZ' + XY'Z'
X' + XY + XZ' (1+Y')
X' + XY + XZ'
X' + X(Y+Z')
X' + Y + Z' [ T10 A]
 
Posted on 09-14-07 12:41 AM     Reply [Subscribe]
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Thank you so much guys. I missed the class and i dont know anyone in my class. This is the reason i posted this stuff here. And yeah smileypkr and thapap thanks for the link. Its' great i would be digging more into it.
 


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