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Posted on 12-06-09 11:31 PM     Reply [Subscribe]
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Your dimensions are right. (A-A1) is a 4x4 matrix and B1 is a 4x2 matrix which implies your Am matrix is 2x4. 

I just tried it in matlab. Type this in your program or command window after defining the matrices A, B1, A1;

Am=B1\(A-A1); remember it's \ not /

However, Am is coming out to be a zero matrix. I don't know if that is right. Solution from matlab:

A =

         0    1.0000         0   -0.0001
    7.5781   21.2169   -2.4152   -6.1767
         0   -0.0004         0    1.0001
   27.2402   78.6220   -8.6725  -22.9705


A1 =

         0    1.0000         0         0
    7.5781   21.2169   -2.4152   -6.1767
         0         0         0    1.0000
   27.2402   78.6220   -8.6725  -22.9705


B1 =

         0         0
    1.0000    0.0022
         0         0
         0    1.0000


Am =

     0     0     0     0
     0     0     0     0

 
Posted on 12-07-09 1:59 AM     Reply [Subscribe]
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Thank you Santosh.It was great help.

 
Posted on 12-07-09 4:00 AM     Reply [Subscribe]
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Keep it up guys, it's a good thread. Jaach ma chai malai yeso dekhau hai......bro haru

 
Posted on 12-07-09 2:44 PM     Reply [Subscribe]
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cheers for the guy like santosh 1984.. guys like you are new hope for sajha.....Nepal ta kaaataam bhayooo ghou....
 
Posted on 12-07-09 3:59 PM     Reply [Subscribe]
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If Am = 0 then A = A1. Clearly that is not true. Look at A(2,3) = -0.0004 and A1(2,3) = 0.
Small difference, I suppose. I wonder if this is more subtle?

 


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