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manab
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Posted on 05-10-05 7:08
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Three guys went to a restaurant and ordered lunch. The check came up to $30 and each paid $10. Then the manager found out that there was a mistake in billing. the check was only for $25. So the manager gave $5 to the bell boy and asked him to return to the guys. The bell boy pocketed $2 from the $5 and gave $3 to the guys and they took $1 each. But the problem is: It looks like each one of them got $1 back and so paid $9 for the meal. If we total this it amounts to $27 ($9*3) and the bell boy kept $2 and this totals to $29, where is the remaining $1? I have heard this before in Nepal but someone please help solve this....it is eating my head for a long time. thanks
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sweetP
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Posted on 05-10-05 7:17
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manab, 9*3=27, this includes the $2 that the waiter took. So no need to add $2 to $27 again.
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hurray
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Posted on 05-10-05 7:22
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Ok. Manab, the problem lies in the way the question is being asked. Here's the solution: Price paid by three guys should equal to the price recieved by the restaurant, right? And the price recieved by the restaurant = price recieved by the manager + price recieved by the bell boy, right? So, the guys paid $27 (3*$9) dollars in total for lunch (even though $25 was the actual cost), which is equal to what the manager recieved ($25) and what the bellboy recieved ($2). So, that $1 dollar which had you confused did not go anywhere; it got lost when the question was asked, and I have already said, the question has a flaw.
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Poonte
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Posted on 05-10-05 7:28
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खै के हो के? आफुले त न question बुझ्या हो, न answer ले sense ला हो। पुन्टे ज्यान को खप्परै सानो। हिसाब भनेसी पिसाबै आउने!
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AeutiKT
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Posted on 05-10-05 8:45
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no solution is the answer
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thees_keta
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Posted on 05-10-05 6:01
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aaaaa, yo question ta hamro SLC ko test ma pani aaye ko thyio....tara i stapled 100rs on that page. i hope i got it rite.
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